
Cisplatin
6. Transition Metal Chemistry
| The transition metals, also called the d-block elements, are found in groups 3-12 of the periodic table. These elements make the transition between the representative metals in groups 1 and 2 and the metalloids, representative metals, and nonmetals in groups 13-18. Moreover, it is in this block of elements in the periodic table that the d-orbitals are being filled with electrons. For example, elements in the first group of the d-block (group 3 of the periodic table: scandium, yttrium, lanthanum, and actinium) each have one d-electron. Likewise, elements in the eighth group of the d-block (group 10 of the periodic table: nickel, palladium, and platinum) each have eight d-electrons when in the +2 oxidation state. |

Figure 1. The oxidation (valence) states of the d-block elements. The orange blocks mark the common oxidation numbers for each element; the green blocks mark the other known states. Reprinted with permission.1Another common feature of the transition metals is their size. To understand why the d-metals are roughly the same size, we need to examine two competing effects: nuclear charge and electron-electron repulsions. As one moves across the periodic table, the size (that is, the atomic radius) of elements generally decreases due to increasing nuclear charge. The increasing nuclear charge is usually more significant than the electron-electron repulsions resulting from the addition of electrons as one moves across a period. In keeping with this trend, transition metals also generally decrease in size as one moves from left to right across the d-block. Here, the exceptionally weak shielding offered by the d-electrons causes these electrons to experience a greater nuclear charge and be pulled more strongly toward the nucleus. The last few elements in each row of the d-block are slightly larger than those preceding them; here, electron-electron repulsions outweigh increasing nuclear charge as the d-orbitals are filled. The trend of decreasing size is most pronounced in row 6 of the periodic table (the third row of the d-block, in which the 5d-orbitals are being filled). The third row of the d-block is interrupted by the lanthanide elements, in which the 4f-orbital is being filled. Like d-electrons, electrons in f-orbitals are also ineffective at shielding nuclear charge; the increased nuclear charge in the third row transition metals causes them to be smaller than expected and virtually identical in size to the second row transition metals.

Figure 2. The atomic radii of the d-block elements (in picometers). Notice the similarity of all the values, and in particular the close similarity between the second and third rows as a result of the lanthanide contraction. Reprinted with permission.1In addition to making the third row transition metals smaller, the lanthanide contraction also makes them less reactive because the valence electrons are relatively close to the nucleus and not available for chemical reactions. In short, several generalizations may be made about the transition metals, or d-metals: most transition metals have a number of possible oxidation states. Also, the d-metals are all roughly the same size. This is particularly noticeable when comparing the second and third row d-metals. Due to the lanthanide contraction, the third row d-metals are approximately the same size as the second row d-metals; the lanthanide contraction also causes the third row d-metals to be relatively inert. The inertness of the third row transition metals has many benefits. For example, these metalsparticularly gold and platinumare often used in jewelry. Furthermore, these metalsspecifically, platinumshould be able to conduct an electric current but not react with their surroundings. For this reason, Barnett Rosenberg and his coworkers chose platinum as an electrode material in their original experiments to study the effect of electric fields on E. coli. However, as we have seen in the module on the role of platinum electrodes, even though their choice was based on sound chemical principles, they obtained unexpected results, which led to the serendipitous discovery of cisplatin. Transition Metal Complexes1 Transition metals are excellent Lewis acids and accept electron density from many molecules or ions that act as Lewis bases; when a Lewis base donates its electron pair to a Lewis acid, it is said to coordinate to the Lewis acid and form a coordinate covalent bond. When Lewis bases coordinate to metals acting as Lewis acids and form an integral structural unit, a coordination compound is formed. In this type of compound, or complex, the Lewis bases are called ligands. One of the first known coordination compounds was Peyrones Chloride (also known as cis-diamminedichloroplatinum(II), or cis-DDP), first reported in 1845. This compound was not fully understood until 1893, when Alfred Werner deduced its structure and described cis-DDP and its trans isomer in a landmark paper.

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Figure 3. (a) The orientation of the five d-orbitals with respect to the ligands of an octahedral complex: the degenerate e pair, and the degenerate t triplet. Reprinted with permission.3 (b) Splitting of the five d-orbitals by an octahedral field.We use similar logic to explain the crystal field splitting of the d-orbitals in a four-coordinate, tetrahedral complex. One way to represent a tetrahedral species is to show four ligands (treated as point charges in crystal field theory) on alternating corners of a cube. In a tetrahedral complex, the ligands do not point directly at any of the five d-orbitals, but they come close to the dxy, dzx, and dyz orbitals, which are directed toward the edges of the cube, as shown in Figure 4(a); these orbitals are raised in energy and are degenerate. The dz2 and the dx2-y2 orbitals point toward the sides of the cube and are therefore directed away from the attached ligands; these two orbitals are lowered in energy and are degenerate. The relative energies (and crystal field splitting) of the five d-orbitals in a tetrahedral complex are shown in Figure 4(b).
Crystal field theory also explains the four-coordinate, square planar geometry. In this case, we imagine an octahedral complex in which the ligands on the z-axis (that is, those interacting most directly with the dz2 orbital) are removed. The dz2 orbital is therefore lowered in energy. Furthermore, the other d-orbitals having z-characterspecifically, the dzx and dyz orbitalsalso decrease in energy. However, since the ligands are all now in the xy plane, both d-orbitals having x- and y-characternamely, the dx2-y2 and the dxy orbitalsare raised in energy. The crystal field splitting pattern of a square planar complex is shown in Figure 5.Figure 4. (a) The effect of a tetrahedral crystal field on a set of d-orbitals is to split them into two sets; the e pair (which point less directly at the ligands) lie lower in energy than the t triplet. Reprinted with permission.3 (b) Splitting of the five d-orbitals by a tetrahedral field.
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Figure 5. (a) An octahedral complex that (b) undergoes z-axis elongation such that it becomes distorted and (c) finally reaches the square planar limit. Reprinted with permission.2What determines whether a four-coordinate transition metal complex is tetrahedral or square planar? The answer lies in the number of d-electrons in the central transition metal. If the metal has eight d-electrons, as is the case for Pt2+, it is energetically advantageous for the complex to adopt a square planar geometry. In this case, the eight d-electrons will achieve some stabilization in energy by occupying the dzx, dyz, dz2, and dxy orbitals. Formation of Cisplatin under the Experimental Conditions Now that we have some background in transition metal chemistry, particularly transition metal complexes, we can understand how cisplatin, or cis-diamminedichloroplatinum(II), was generated under the original reaction conditions in which elongation of E. coli bacterial cells was observed. As we saw in the electrochemistry module, a divalent platinum ion (Pt2+) could be generated when an electric current was supplied to the supposedly inert platinum electrodes in the continuous culture chamber. Moreover, as we saw in the control experiments module, solutions containing either ammonium ion or chloride ion or both tested positive for the presence of an oxidizing agent using the potassium iodidestarch test. One of the oxidizing agents presentnamely, cis-diamminedichloroplatinum(II)was responsible for bacterial elongation. How does cis-PtII(NH3)2Cl2 form from Pt2+, NH4+, and Cl- ions? Remember that in an aqueous solution, ammonium ion (NH4+) is in equilibrium with its conjugate base, ammonia (NH3):
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(3) Shriver, D. F., Atkins, P., Langford, C. H. Inorganic Chemistry, 2nd ed. W. H. Freeman and Company: New York, 1994, Chapter 6.
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